IQ Question

Each letter is assigned a different number, like 5 and d, and you get Robert by adding each into the other.

Yeah, something like that.

 

D=5, T=0 because 5+5=10, then you solve it from there.

5ONAL5
+GERAL5
--------
ROBER0

D=5, O=2, N=6, A=4, L=8, G=1, E=9, R=7, B=3, T=0

 

Without additional clues, I am not sure this problem is solvable.

But some letters can be inferred.

Frist from "o + e = o" we know that either o or e could be 0. If e is 0, then it would be impossible for a + a = e to be correct. So o has to be 0, it follows e is 9, and a is 4, and l > 5.

No much else I can come up at this moment.

 

Damn, did he say the letters were case-insensitive?

 

The question is moot.

 

I think it's something cooked up by the liberals to support gay marriage...

 

I just subsituted the remaining numbers here and there and it eventually worked out, not the genius way of doing it, but it worked!

If you didn't give me d=5 it would have taken forever, so I imagine there's an easier way of doing it rather than proccess of elimination. And I have a feeling that I've seen this type of puzzle somewhere before...

 

I did it so it is possible because i'm usually a single digit guy as far as IQ tests go

Key was noticing there were ten letters...then looking for patterns. For instance.... o+e =o. e couldn't be zero since it was already taken, so there must have been a 1 carried forward. o+e+1=o. So....e=-1 -- which didn't make sense, so then i realized o+e+1 could equal o +10. suddenly E=9.

And so on....(the 1's carried forward also helped decypher stuff) Clearly...i've got too much time on my hands today.

 

What's the question stem? Figure out the assigned value for each letter?

 

OK, now that I know we can assume 1) letters are case-insensitive and 2) each letter represents a unique digit. The problem is therefore completely solvable without random guessing.

For me, the path starts from o + e = o

Since we know neither o nor e can be 0, so 9 has to be involved. It only makes sense e is 9. It then follows a is 4, from a + a = e.

Since 5 (D) + G = R, R is one of 6, 7, 8.

Since L + L = R and it produces a carry-over, L is one of 6, 7, or 8, more over, R has to be an odd number because of the carry-over from 5 (D) + 5 (D) = 10. So R = 7. It follows that L = 8, G = 1.

N + 7 (R) = B produces a carry-over. Thus, among the rest unpicked digits, 2, 3, 6, N has to be 6. It follows that B = 3, O =2.

 

Apparently, these things are called alphametics and there are more examples, I remembered these from somewhere so I searched donald+gerald=robert and found this page: http://www.geocities.com/Athens/Agora/2160/puzzlemenu.html Kind of addicting... I got the used+sex=words on the hard column without cheating.

 

It means D is 4 + 1